100x^2+8=108

Solution for 100x^2+8=108 equation:

100x^2+8=108

We move all terms to the left:

100x^2+8-(108)=0

We add all the numbers together, and all the variables

100x^2-100=0

a = 100; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·100·(-100)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*100}=\frac{-200}{200}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*100}=\frac{200}{200}
=1
$